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This Concept Map, created with IHMC CmapTools, has information related to: Triangles, Triangles have Area, prove that two segemnts made of sides of the triangle are congruent first you prove that two triangles are congruent, cos ∠ is <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mfrac> <mtext> A </mtext> <mtext> H </mtext> </mfrac> </mrow> </math>, 30-60 right triangles tip <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> If the short leg is length a; longer leg is a </mtext> <msqrt> <mtext> 3 </mtext> </msqrt> <mtext> ; hypot. is 2a units </mtext> </mrow> </math>, isosoles triangle can be solved with <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> pythagorean theorem </mtext> <mmultiscripts> <mtext> c </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> <mtext> = </mtext> <mmultiscripts> <mtext> a </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> <mtext> + </mtext> <mmultiscripts> <mtext> b </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> </mrow> </math>, prove that two segemnts made of sides of the triangle are congruent then use CPCTC, Congruence is when the shape and size is identicle between two objects, 30-60 right triangles can be solved with <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> pythagorean theorem </mtext> <mmultiscripts> <mtext> c </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> <mtext> = </mtext> <mmultiscripts> <mtext> a </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> <mtext> + </mtext> <mmultiscripts> <mtext> b </mtext> <none/> <mtext> 2 </mtext> </mmultiscripts> </mrow> </math>, In Right Triangles with 30-60-90 angles are 30-60 right triangles, In Right Triangles with 45 degree angles are isosoles triangle, HL which is if the hypotenuse and a leg are the same then both triangles are acongruent, In Equilateral Triangles you find all three sides are equal length, Classified details In Equilateral Triangles, isosoles triangle tip <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> If each leg is a units then the hypoteneuse is a </mtext> <msqrt> <mtext> 2 </mtext> </msqrt> <mtext> units </mtext> </mrow> </math>, a missing side by trigonometry memorize tan ∠, HL which is hypotenuse - leg, sin ∠ is <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mfrac> <mtext> O </mtext> <mtext> H </mtext> </mfrac> </mrow> </math>, prove that two triangles are congruent built of conditions, <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <mtext> If the short leg is length a; longer leg is a </mtext> <msqrt> <mtext> 3 </mtext> </msqrt> <mtext> ; hypot. is 2a units </mtext> </mrow> </math> note <math xmlns="http://www.w3.org/1998/Math/MathML"> <mrow> <msqrt> <mtext> 3 </mtext> </msqrt> </mrow> </math>, In Right Triangles you find it has one 90 degree angle