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Livelli della MO21, livello 5 <<[in1 OP1 C1] OP2 [in2 OP3 C2] =Out>> Out = in1² + 2in1·in2 + in2² Out = in1² - 2in1·in2 + in2² Out = Int[Radq(in1² + in2²)] [inx OP C] OP iny = Out) |in1-in2| <= Rnd <= in1+in2 if c<k then out=c,c+1....k else out=k,k+1.....c + livello 4 da completare + aggiunto << · >>, Livelli della MO21 livello3 M OP C K OP C q OP C R1 OP C R2 OP C (in1 OP1 in2) OP2 C (in1 OP1 C) OP2 in2 Out = (in12)² OP in21 <<inx²>> <<inx OP C>> +livello 2, livello 5 <<[in1 OP1 C1] OP2 [in2 OP3 C2] =Out>> Out = in1² + 2in1·in2 + in2² Out = in1² - 2in1·in2 + in2² Out = Int[Radq(in1² + in2²)] [inx OP C] OP iny = Out) |in1-in2| <= Rnd <= in1+in2 if c<k then out=c,c+1....k else out=k,k+1.....c + livello 4 [inxopc]opiny l'input va randomizzato ad ogni tentativo?, Livelli della MO21 livello 4 Rx [In1 OP C1] OP [In2 OP C2] = Out [in1 OP1 C] OP2 [in2 OP1 C] =Out [in1 OP1 in2] OP2 [in1 OP3 in2] Out = (in1² + in2²) Out = |in1² - in2²|=(in1+in2)·|in1-in2| min(in1, in2) <= rnd <= max(in1,in2); out = rnd out = rnd > max(in1, in2) out = rnd < min(in1, in2) + livello 3, livello 2 R1 R2 M (in1 OP in2) OP C (in1 OP C) OP in2 <<in1²>> <<in2²>> <<in1 OP C>> <<in2 OP C>> + livello 1 aggiunti << · >>, Livelli della MO21 livello1 out=in1 op in2 Parità confronto(>,<,=) k q <<out = inx>>, Livelli della MO21 livello 2 R1 R2 M (in1 OP in2) OP C (in1 OP C) OP in2 <<in1²>> <<in2²>> <<in1 OP C>> <<in2 OP C>> + livello 1, [inxopc]opiny l'input va randomizzato ad ogni tentativo? ???? sì, x significa che ogni volta si sceglie a caso 1 o 2., livello3 M OP C K OP C q OP C R1 OP C R2 OP C (in1 OP1 in2) OP2 C (in1 OP1 C) OP2 in2 Out = (in12)² OP in21 <<inx²>> <<inx OP C>> +livello 2 aggiunti << · >>, Livelli della MO21 livello 5 <<[in1 OP1 C1] OP2 [in2 OP3 C2] =Out>> Out = in1² + 2in1·in2 + in2² Out = in1² - 2in1·in2 + in2² Out = Int[Radq(in1² + in2²)] [inx OP C] OP iny = Out) |in1-in2| <= Rnd <= in1+in2 if c<k then out=c,c+1....k else out=k,k+1.....c + livello 4